+#include <errno.h>
+#include <limits.h>
+#include <math.h>
+#include <stdio.h>
+#include <stdlib.h>
+#include <string.h>
+#include <sys/time.h>
+#include <unistd.h>
+
+int
+main (int argc, char *argv[])
+{
+ const char *program_name = argv[0];
+ double timeout;
+
+ if (argc < 3)
+ {
+ fprintf (stderr,
+ "setitimer-helper: runs a program with a virtual CPU limit\n"
+ "usage: %s TIMEOUT PROGRAM [ARG...]\n"
+ " where TIMEOUT is the virtual CPU limit, in seconds,\n"
+ " and remaining arguments specify the program to run\n"
+ " and its argument.\n",
+ program_name);
+ return EXIT_FAILURE;
+ }
+
+ timeout = strtod (argv[1], NULL);
+ if (timeout >= 0.0 && timeout < LONG_MAX)
+ {
+ struct itimerval it;
+
+ it.it_interval.tv_sec = 0;
+ it.it_interval.tv_usec = 0;
+ it.it_value.tv_sec = timeout;
+ it.it_value.tv_usec = (timeout - floor (timeout)) * 1000000;
+ if (setitimer (ITIMER_VIRTUAL, &it, NULL) < 0)
+ fprintf (stderr, "%s: setitimer: %s\n",
+ program_name, strerror (errno));
+ }
+ else
+ fprintf (stderr, "%s: invalid timeout value \"%s\"\n",
+ program_name, argv[1]);
+
+ execvp (argv[2], &argv[2]);
+ fprintf (stderr, "%s: couldn't exec \"%s\": %s\n",
+ program_name, argv[2], strerror (errno));
+ return EXIT_FAILURE;
+}