Fix %' grouping in printf().

I hope this finally takes care of it.

diff --git a/src/lib/stdio.c b/src/lib/stdio.c
index bae257feb73da6bc4e64806feaaeca2488cbd76f..98b63030b4d2925127b77f14b4f8a1394fa61066 100644 (file)
--- a/src/lib/stdio.c
+++ b/src/lib/stdio.c
@@ -469,23 +469,21 @@ format_integer (uintmax_t value, bool negative, const struct integer_base *b,
   const char *signifier;        /* b->signifier or "". */
   int precision;                /* Rendered precision. */
   int pad_cnt;                  /* # of pad characters to fill field width. */
-  int group_cnt;                /* # of digits grouped so far. */
+  int digit_cnt;                /* # of digits output so far. */
 
   /* Accumulate digits into buffer.
      This algorithm produces digits in reverse order, so later we
      will output the buffer's content in reverse.  This is also
      the reason that later we append zeros and the sign. */
   cp = buf;
-  group_cnt = 0;
+  digit_cnt = 0;
   while (value > 0) 
     {
-      if ((c->flags & GROUP) && group_cnt++ == b->group) 
-        {
-          *cp++ = ',';
-          group_cnt = 0; 
-        }
+      if ((c->flags & GROUP) && digit_cnt > 0 && digit_cnt % b->group == 0)
+        *cp++ = ',';
       *cp++ = b->digits[value % b->base];
       value /= b->base;
+      digit_cnt++;
     }
 
   /* Append enough zeros to match precision.