-/* Copyright (C) 1991,1992,1993,1996,1997,1998,1999,2000,2001,2002,2003,2004,2005,2006,2009
- Free Software Foundation, Inc.
+/* Copyright (C) 1991-1993, 1996-2006, 2009-2011 Free Software Foundation, Inc.
This file is part of the GNU C Library.
This program is free software; you can redistribute it and/or modify
/* We found a table entry. Now see whether the
character we are currently at has the same
equivalance class value. */
- int len = weights[idx];
+ int len = weights[idx & 0xffffff];
int32_t idx2;
const UCHAR *np = (const UCHAR *) n;
idx2 = findidx (&np);
- if (idx2 != 0 && len == weights[idx2])
+ if (idx2 != 0
+ && (idx >> 24) == (idx2 >> 24)
+ && len == weights[idx2 & 0xffffff])
{
int cnt = 0;
+ idx &= 0xffffff;
+ idx2 &= 0xffffff;
+
while (cnt < len
&& (weights[idx + 1 + cnt]
== weights[idx2 + 1 + cnt]))