-# Only the two-pass algorithm can be expected to produce
-# proper third and fourth moments here.
-1000001 1000002 1000003 1000004 => W=4.000 M1=1000002.500 M2=1.667 M3=0.000 M4=-1.200
+# We used to have an example for which only the two-pass algorithm
+# produced reasonable results, but the provisional means algorithm
+# does better, so there aren't any extra tests here.