Invert the priority scheme, so that PRI_MIN is now the lowest priority

[pintos-anon] / src / tests / threads / priority-donate-one.c

diff --git a/src/tests/threads/priority-donate-one.c b/src/tests/threads/priority-donate-one.c
index 603a7fe45a9b3469133f21aef75041d596a2981a..2a67b52e0960f99bbfba53ba757f8c2967b17cb4 100644 (file)
--- a/src/tests/threads/priority-donate-one.c
+++ b/src/tests/threads/priority-donate-one.c
@@ -31,12 +31,12 @@ test_priority_donate_one (void)
 
   lock_init (&lock);
   lock_acquire (&lock);
-  thread_create ("acquire1", PRI_DEFAULT - 1, acquire1_thread_func, &lock);
+  thread_create ("acquire1", PRI_DEFAULT + 1, acquire1_thread_func, &lock);
   msg ("This thread should have priority %d.  Actual priority: %d.",
-       PRI_DEFAULT - 1, thread_get_priority ());
-  thread_create ("acquire2", PRI_DEFAULT - 2, acquire2_thread_func, &lock);
+       PRI_DEFAULT + 1, thread_get_priority ());
+  thread_create ("acquire2", PRI_DEFAULT + 2, acquire2_thread_func, &lock);
   msg ("This thread should have priority %d.  Actual priority: %d.",
-       PRI_DEFAULT - 2, thread_get_priority ());
+       PRI_DEFAULT + 2, thread_get_priority ());
   lock_release (&lock);
   msg ("acquire2, acquire1 must already have finished, in that order.");
   msg ("This should be the last line before finishing this test.");